If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-20x-4500=0
a = 1; b = -20; c = -4500;
Δ = b2-4ac
Δ = -202-4·1·(-4500)
Δ = 18400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18400}=\sqrt{400*46}=\sqrt{400}*\sqrt{46}=20\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{46}}{2*1}=\frac{20-20\sqrt{46}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{46}}{2*1}=\frac{20+20\sqrt{46}}{2} $
| 7f+10f+3=0 | | -8(2v+6)=-24-8v | | w/3+6=10 | | 18x^2+11x-16=0 | | 100y=4 | | 2f+1=3f-15 | | -2(4+k)=-14 | | 65=4q+9 | | 8x-3(2x-1)=7 | | 3x+2-5=-12 | | 2f-5=7 | | 4-7^(2x)=1 | | x^2-64,600=0 | | (5x-3)(-2x+3)=0 | | 70=7(m+2.3) | | 15x+4=40-3x | | 2r-2=r-4 | | X=15ส่วนx+12 | | -10x+32=14 | | 3x-2+5=0 | | X×2x=512 | | 4s+5=2s-10 | | 2+4t=20-2t | | -2(5+x)=21 | | 3(y+15)=47+y | | 5x=15/9 | | 6x-15=10x+10 | | 12n-15=129n= | | 2(c-10)=6 | | 4n-20=60n= | | 8+6x=x+6 | | 3n+5=20n= |